Calculate GATE Score

Normalization mark of $j^{th}$ candidate in the $i^{th}$ session $\hat{M}ij$ is given by

${\hat{M}}_{ij}=\frac{{\overline{M}}_t^g-M_q^g}{{\overline{M}}_{ti}-M_{iq}}\left(M_{ij}-M_{iq}\right)+M_q^g$

where

$M_{ij}$ : is the actual marks obtained by the $j^{th}$ candidate in $i^{th}$ session

${\overline{M}}_t^g$ : is the average of the top 0.1% of the candidates considering all sessions

$M_q^g$ : is the sum of mean and standard deviation marks of the candidates in the paper considering all sessions

${\overline{M}}_{ti}$ : is the average marks of the top 0.1% of the candidates in the $i^{th}$ session

$M_{iq}$ : is the sum of the mean marks and standard deviation of the $i^{th}$ session

For all papers for which there is only one session, actual marks obtained by the candidates will be used for calculating the GATE 2019 Score. For papers in multi-sessions, normalized marks will be calculated corresponding to the raw marks obtained by a candidate and the GATE 2019 Score will be calculated based on the normalized marks.

GATE 2019 score will be calculated using the formula

$GATE Score=S_q+\left(S_t-S_q\right)\frac{\left(M-M_q\right)}{\left({\overline{M}}_t-M_q\right)}$

In the above formulae

$M$ : marks obtained by the candidate (actual marks for single session papers and normalized marks for multi-session papers)

$M_q$ : is the qualifying marks for general category candidate in the paper

${\overline{M}}_t$ : is the mean of marks of top 0.1% or top 10 (whichever is larger) of the candidates who appeared in the paper (in case of multi-session papers including all sessions)