In the circuit shown below, the node voltage V_{A} is ___________ V.
$v\left(t\right)=100\mathrm{sin}\left(\omega t\right)$ ,
$i\left(t\right)=10\mathrm{sin}\left(\omega t-{60}^{\xb0}\right)+2\mathrm{sin}\left(3\omega t\right)+5\mathrm{sin}\left(5\omega t\right)$
The average power consumed by the load, in W, is___________.
The voltages developed across the 3 Ω and 2 Ω resistors shown in the figure are 6V and 2V respectively, with the polarity as marked. What is the power (in Watt) delivered by the 5V voltage source?
The self inductance of the primary winding of a single phase, 50 Hz, transformer is 800 mH, and that of the secondary winding is 600 mH. The mutual inductance between these two windings is 480 mH. The secondary winding of this transformer is short circuited and the primary winding is connected to a 50 Hz, single phase, sinusoidal voltage source. The current flowing in both the winding is less than their respective rated currents. The resistance of both windings can be neglected. In this connection, what is the effective inductance (in mH) seen by the source?
In the given circuit, the parameter k is positive, and the power dissipated in the 2$\mathrm{\Omega}$ resistor is 12.5 W. The value of k is________.
The current i (in Ampere) in the 2 $\mathrm{\Omega}$ resistor of the given network is ____ .
In the given network ${V}_{1}=100\angle {0}^{\xb0}$0°V, ${V}_{2}=100\angle -{120}^{\xb0}$V, ${V}_{3}=100\angle +{120}^{\xb0}$V. The phasor current i (in Ampere) is
The line A to neutral voltage is A10∠15^{o}V for a balanced three phase star-connected load with phase sequence ABC. The voltage of line B with respect to line C is given by
The power delivered by the current source, in the figure, is ________.
In the circuit shown below, the current through the inductor is
A two-phase load draws the following phase currents: ${i}_{1}\left(t\right)={I}_{m}\mathrm{sin}\left(\omega t-{\Phi}_{1}\right)$, ${i}_{2}\left(t\right)={I}_{m}\mathrm{cos}\left(\omega t-{\Phi}_{2}\right)$.These currents are balanced if ${\Phi}_{1}$ is equal to
The average power delivered to an impedance (4-j3)$\Omega $ by a current $5\mathrm{cos}\left(100\pi t+100\right)A$ is
If V_{A}-V_{B}=6V, then V_{C}-V_{D} is
The r.m.s value of the current i (t) in the circuit shown below is
The voltage applied to a circuit is 100 $\sqrt{2}$ cos (100$\pi $t) volts and the circuit draws a current of 10 $\sqrt{2}$ sin (100$\pi $t + $\pi $ / 4) amperes. Taking the voltage as the reference phasor, the phasor representation of the current in amperes is
The input voltage given to a converter is ${v}_{i}=100\sqrt{2}\mathrm{sin}\left(100\pi t\right)\mathrm{V}$
The current drawn by the converter is ${i}_{i}=\left(10\sqrt{2}\mathrm{sin}\left(100\pi t-\raisebox{1ex}{$\pi $}\!\left/ \!\raisebox{-1ex}{$3$}\right.\right)+5\sqrt{2}\mathrm{sin}\left(300\pi t+\raisebox{1ex}{$\pi $}\!\left/ \!\raisebox{-1ex}{$4$}\right.\right)+2\sqrt{2}\mathrm{sin}\left(500\pi t-\raisebox{1ex}{$\pi $}\!\left/ \!\raisebox{-1ex}{$6$}\right.\right)\right)\mathrm{A}$
The input power factor of the converter is
The active power drawn by the converter is
An RLC circuit with relevant data is given below.
The power dissipated in the resistor R is
The current ${\overline{)I}}_{C}$ in the figure above is
As shown in the figure, a 1Ω resistance is connected across a source that has a load line v+ i = 100. The current through the resistance is
If the 12Ω resistor draws a current of 1A as shown in the figure, the value of resistance R is
The current through the 2 kΩ resistance in the circuit shown is
The equivalent capacitance of the input loop of the circuit shown is
For the circuit shown, find out the current flowing through the 2Ω resistance. Also identify the changes to be made to double the current through the 2Ω resistance
The Thevenin’s equivalent of a circuit operation at ω = 5 rads/s, has ${V}_{\mathrm{oc}}=3.71\angle -15.9\xb0V\mathrm{and}{Z}_{\mathrm{o}}=2.38-j0.667\Omega .$At this frequency, the minimal realization of the Thevenin’s impedance will have a
Assuming ideal elements in the circuit shown below, the voltage V_{ab} will be
In the circuit shown in the figure, the value of the current i will be given by
The state equation for the current I_{1} in the network shown below in terms of the voltage V_{x} and the independent source V, is given by
In the figure given below all phasors are with reference to the potential at point "O". The locus of voltage phasor V_{YX} as R is varied from zero to infinity is shown by
(A)
(B)
(C)
(D)
A 3 V DC supply with an internal resistance of 2 Ω supplies a passive non-linear resistance characterized by the relation V_{NL} = I^{2}_{NL}. The power dissipated in the non-linear resistance is