GATE Papers >> EEE >> 2015 >> Question No 5

Question No. 5 EEE | GATE 2015

Given set A = {2, 3, 4, 5} and Set B = {11, 12, 13, 14, 15}, two numbers are randomly selected, one from each set. What is probability that the sum of the two numbers equals 16?


Answer : (A) 0.20


Solution of Question No 5 of GATE 2015 EEE Paper

To make the sum equal to 16, the following combinations can be considered.

2 + 14 ; 3 + 13 ; 4 + 12 ; 5 + 11

$ \begin{array}{l}{\mathrm P}_{2,14}=\frac14\times\frac15={\mathrm P}_{3,13}={\mathrm P}_{4,12}={\mathrm P}_{5,11}\\{\mathrm P}_{16}={\mathrm P}_{2,14}+{\mathrm P}_{3,13}+{\mathrm P}_{4,12}+{\mathrm P}_{5,11}\\=\frac1{20}+\frac1{20}+\frac1{20}+\frac1{20}=\frac15=0.20\end{array} $

Comments
No Comments
Leave a comment
Go