GATE Papers >> CSE >> 2016 >> Question No 40

Question No. 40 CSE | GATE 2016

Consider the two cascaded 2-to-1 multiplexers as shown in the figure.

The minimal sum of products form of the output $X$ is


Answer : (D) Q¯ R¯ +PQR


Solution of Question No 40 of GATE 2016 CSE Paper

MUX-1 output ⇒ $ \overline P\left(0\right)+P\left(R\right)=PR $

MUX-2 output ⇒ $ X=\overline Q\left(\overline R\right)+Q\left(PR\right) $

                     $ =\overline Q\overline R+PQR $

Comments
26I1iE http://pills2sale.com/ levitra nizagara

Posted on  18/10/2020 20:35:36  by  dobsonz
7761zG https://www.quora.com/What-the-top-SEO-keywords-for-essay-you-know/answer/Alan-Smith-1772 write my essay

Posted on  04/12/2020 01:54:19  by  dobson
mZj9rp http://xnxx.in.net/ xnxx videos

Posted on  13/12/2020 00:30:26  by  johnan
f8iZS5 https://writemyessayforme.web.fc2.com/

Posted on  13/12/2020 05:19:09  by  dobson
c4mXaD https://writemyessayforme.web.fc2.com/#writemyessay

Posted on  15/12/2020 06:19:33  by  dobson
znCqzm https://writemyessayforme.web.fc2.com/octavio-paz-essay-day-of-the-dead.html

Posted on  09/01/2021 12:15:46  by  dobson
MDpPWQ http://waldorfdollshop.us/ waldorf doll

Posted on  09/01/2021 16:36:57  by  johnanz
TAPXvI https://beeg.x.fc2.com/

Posted on  26/01/2021 17:30:21  by  markus
n4wZ2o https://buyzudena.web.fc2.com/

Posted on  27/01/2021 13:51:10  by  markus
Leave a comment