GATE Papers >> CSE >> 2016 >> Question No 40

Question No. 40 CSE | GATE 2016

Consider the two cascaded 2-to-1 multiplexers as shown in the figure.

The minimal sum of products form of the output $X$ is


Answer : (D) Q¯ R¯ +PQR


Solution of Question No 40 of GATE 2016 CSE Paper

MUX-1 output ⇒ $ \overline P\left(0\right)+P\left(R\right)=PR $

MUX-2 output ⇒ $ X=\overline Q\left(\overline R\right)+Q\left(PR\right) $

                     $ =\overline Q\overline R+PQR $

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