# GATE Papers >> CSE >> 2015 >> Question No 138

Question No. 138

Assume that the bandwidth for a TCP connection is 1048560 bits/sec. Let $\alpha$ be the value of RIT in milliseconds (rounded off to the nearest integer) after which the TCP window scale option is needed. Let $\beta$ be the maximum possible window size with window scale option. Then the values of $\alpha$ and $\beta$ are

##### Answer : (C) 500 milliseconds, 65535 X 214

Solution of Question No 138 of GATE 2015 CSE Paper

Maximum windows size is the amount of data that can be transmitted in an RTT.

$\therefore\;\mathrm{RTT}=\frac{65535\times8}{1048560\;\mathrm{bps}}=500\;\mathrm{ms}$

For scaling factor 14 bits are used

$\therefore$  Option (c) is correct.