GATE Papers >> CSE >> 2015 >> Question No 136

Question No. 136 CSE | GATE 2015

Consider the following routing table at an IP router.

Network No. Net Mask    Next Hop
128.96.170.0     255.255.254.0       Interface 0     
128.96.168.0 255.255.254.0   Interface 1
128.96.166.0 255.255.254.0    R2
128.96.164.0 255.255.252.0   R3
0.0.0.0 Default   R4

For each IP address in Group I identify the correct choice of the next hop form Group II using the entries from the routing table above.

Group I          Group II
i) 128.96.171.92          a) Interface 0
ii) 128.96.167.151          b) Interface 1
iii) 128.96.163.151          c) R2
iv) 128.96.165.121          d) R3
           e) R4

Answer : (A) i-a, ii-c, iii-e, iv-d


Solution of Question No 136 of GATE 2015 CSE Paper
IP Address Net Mask Network No. Next Hop
128.96.171.92 255.255.254.0 128.96.170.0 Interface 0
128.96.167.151 255.255.254.0 128.96.166.0 R2
128.96.163.151 default 0.0.0.0 R4
128.96.165.121 255.255.252.0 128.96.164.0 R3
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