After the evaluation of the answers, the raw marks obtained by a candidate will be converted to a normalized GATE Score.

The GATE score will be computed using the formula given below.

**Calculation of Normalized Marks for CE, CS, EC, EE and ME papers (multi-session papers)**

In GATE 2018, examination for some papers may be conducted in multi-sessions. Hence, for these papers, a suitable normalization is applied to take into account any variation in the difficulty levels of the question papers across different sessions. The normalization is done based on the fundamental assumption that "in all multi-session GATE papers, the distribution of abilities of candidates is the same across all the sessions". This assumption is justified since the number of candidates appearing in multi-session papers in GATE 2016 is large and the procedure of allocation of session to candidates is random. Further it is also ensured that for the same multi-session paper, the number of candidates allotted in each session is of the same order of magnitude.

Based on the above, and considering various normalization methods, the committee arrived at the following formula for calculating the normalized marks for the multi-session papers.

Normalization mark of ${j}^{th}$ candidate in the ${i}^{th}$ session mij is given by

${\hat{M}}_{ij}=\frac{{\overline{)M}}_{t}^{g}-{M}_{q}^{g}}{{\overline{)M}}_{ti}-{M}_{iq}}\left({M}_{ij}-{M}_{iq}\right)+{M}_{q}^{g}$

where

${M}_{ij}$ : is the actual marks obtained by the ${j}^{th}$ candidate in ${i}^{th}$ session

${\overline{)M}}_{t}^{g}$ : is the average of the top 0.1% of the candidates considering all sessions

${M}_{q}^{g}$ : is the sum of mean and standard deviation marks of the candidates in the paper considering all sessions

${\overline{)M}}_{ti}$ : is the average marks of the top 0.1% of the candidates in the ${i}^{th}$ session

${M}_{iq}$ : is the sum of the mean marks and standard deviation of the ${i}^{th}$ session

After evaluation of the answers, normalized marks based on the above formula will be calculated corresponding to the raw marks obtained by a candidate and the GATE 2018 Score will be calculated based on the normalized marks.

For all papers for which there is only one session, actual marks obtained will be used for calculating the GATE 2018 Score.

GATE 2018 score will be calculated using the formula

$GATEScore={S}_{q}+\left({S}_{t}-{S}_{q}\right)\frac{\left(M-{M}_{q}\right)}{\left({\overline{)M}}_{t}-{M}_{q}\right)}$

In the above formulae

$M$ : marks obtained by the candidate (actual marks for single session papers and normalized marks for multi-session papers)

${M}_{q}$ : is the qualifying marks for general category candidate in the paper

${\overline{)M}}_{t}$ : is the mean of marks of top 0.1% or top 10 (whichever is larger) of the candidates who appeared in the paper (in case of multi-session papers including all sessions)

${S}_{q}$ : 350, is the score assigned to ${M}_{q}$

${S}_{t}$ : 900, is the score assigned to ${\overline{)M}}_{t}$

In the GATE 2018 score formula,
${M}_{q}$
is usually 25 marks (out of 100) or + *σ*, whichever is larger. Here *μ* is the mean and *σ* is the standard deviation of marks of all the candidates who appeared in the paper.